There's a famous museum in the city where Kleofas lives. In the museum, n exhibits (numbered 1 through n) had been displayed for a long time; the i-th of those exhibits has value vi and mass wi.
Then, the museum was bought by a large financial group and started to vary the exhibits. At about the same time, Kleofas... gained interest in the museum, so to say.
You should process q events of three types:
For each event of type 3, let s(m) be the maximum possible total value of stolen exhibits with total mass ≤m.
Formally, let D be the set of numbers of all exhibits that are currently displayed (so initially D = {1, ..., n}). Let P(D) be the set of all subsets of D and let
Then, s(m) is defined as
Compute s(m) for each . Note that the output follows a special format.
The first line of the input contains two space-separated integers n and k (1≤n≤5000, 1≤k≤1000) − the initial number of exhibits in the museum and the maximum interesting mass of stolen exhibits.
Then, n lines follow. The i-th of them contains two space-separated positive integers vi and wi (1≤vi≤1000000, 1≤wi≤1000)− the value and mass of the i-th exhibit.
The next line contains a single integer q (1≤q≤30000)− the number of events.
Each of the next q lines contains the description of one event in the following format:
There will be at most 10000 events of type 1 and at least one event of type 3.
As the number of values s(m) can get large, output the answers to events of type 3 in a special format.
For each event of type 3, consider the values s(m) computed for the question that Kleofas asked in this event; print one line containing a single number
where p=107+19 and q=109+7.
Print the answers to events of type 3 in the order in which they appear in the input.
3 10
30 4
60 6
5 1
9
3
1 42 5
1 20 3
3
2 2
2 4
3
1 40 6
3
556674384
168191145
947033915
181541912
3 1000
100 42
100 47
400 15
4
2 2
2 1
2 3
3
0
In the first sample, the numbers of displayed exhibits and values s(1),...,s(10) for individual events of type 3 are, in order:
The values of individual exhibits are v1=30,v2=60,v3=5,v4=42,v5=20,v6=40 and their masses are w1=4,w2=6,w3=1,w4=5,w5=3,w6=6.
In the second sample, the only question is asked after removing all exhibits, so s(m)=0 for any m.