2163: Harmony Analysis
Time Limit: 2 Sec Memory Limit: 256 MBSubmit: 0 Solved: 0
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Description
The semester is already ending, so Danil made an effort and decided to visit a lesson on harmony analysis to know how does the professor look like, at least. Danil was very bored on this lesson until the teacher gave the group a simple task: find 4 vectors in 4-dimensional space, such that every coordinate of every vector is 1 or -1 and any two vectors are orthogonal. Just as a reminder, two vectors in n-dimensional space are considered to be orthogonal if and only if their scalar product is equal to zero, that is:
Danil quickly managed to come up with the solution for this problem and the teacher noticed that the problem can be solved in a more general case for 2k vectors in 2k-dimensinoal space. When Danil came home, he quickly came up with the solution for this problem. Can you cope with it?
The only line of the input contains a single integer k (0≤k≤9).
Print 2k lines consisting of 2k characters each. The j-th character of the i-th line must be equal to '*' if the j-th coordinate of the i-th vector is equal to -1, and must be equal to '+' if it's equal to +1. It's guaranteed that the answer always exists.
If there are many correct answers, print any.
2
++**
+*+*
++++
+**+
Consider all scalar products in example:
- Vectors 1 and 2: (+1)·(+1)+(+1)·(-1)+(-1)·(+1)+(-1)·(-1)=0
- Vectors 1 and 3: (+1)·(+1)+(+1)·(+1)+(-1)·(+1)+(-1)·(+1)=0
- Vectors 1 and 4: (+1)·(+1)+(+1)·(-1)+(-1)·(-1)+(-1)·(+1)=0
- Vectors 2 and 3: (+1)·(+1)+(-1)·(+1)+(+1)·(+1)+(-1)·(+1)=0
- Vectors 2 and 4: (+1)·(+1)+(-1)·(-1)+(+1)·(-1)+(-1)·(+1)=0
- Vectors 3 and 4: (+1)·(+1)+(+1)·(-1)+(+1)·(-1)+(+1)·(+1)=0