Problem S: 【基础题】最小公倍数（LCM - Least Common Multiple.）

Problem S: 【基础题】最小公倍数（LCM - Least Common Multiple.）

Time Limit: 1 Sec  Memory Limit: 128 MB
Submit: 333  Solved: 103
[Submit] [Status] [Web Board] [Creator:]

Description

输入任意的自然数A, B, 求A , B的最小公倍数。 

Input any natural numbers A, B, and find the least common multiple of A and B.

Input

两个自然数A、B，不超过32767。 

Two natural numbers A, B, not more than 32767.

Output

最小公倍数。

Least Common Multiple.

Sample Input Copy 

3 5

Sample Output Copy 

15
[Submit][Status]