Problem S: 【基础题】最小公倍数(LCM - Least Common Multiple.)

Problem S: 【基础题】最小公倍数(LCM - Least Common Multiple.)

Time Limit: 1 Sec  Memory Limit: 128 MB
Submit: 333  Solved: 103
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Description

输入任意的自然数A, B, 求A , B的最小公倍数。

Input any natural numbers A, B, and find the least common multiple of A and B.

Input

两个自然数A、B,不超过32767。

Two natural numbers A, B, not more than 32767.

Output

最小公倍数。

Least Common Multiple.

Sample Input Copy

3 5

Sample Output Copy

15